3/4x^2+8x+20=0

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Solution for 3/4x^2+8x+20=0 equation: 


x in (-oo:+oo)

(3/4)*x^2+8*x+20 = 0

3/4*x^2+8*x+20 = 0

DELTA = 8^2-(3/4*4*20)

DELTA = 4

DELTA > 0

x = (4^(1/2)-8)/(3/4*2) or x = (-4^(1/2)-8)/(3/4*2)

x = -4 or x = -20/3

x in { -20/3, -4 }

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